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The number 42847

42847 is a composite number with 4 divisors. Its prime factorisation is 7 × 6121. Divisors (4): 1, 7, 6121, 42847.

Number

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How to work it out

  1. 1

    What is special about 42847: a semiprime: 7 × 6121, the product of two primes.

  2. 2

    42847 is composite. Its prime factorisation is

    42847=7×612142847 = 7 \times 6121
  3. 3

    The divisors add up to 48976; without 42847 itself that is 6129, so 42847 is deficient (6129 is less than 42847). Euler's totient φ(42847) = 36720 numbers up to 42847 share no factor with it.

  4. 4

    The digits of 42847 add up to 25, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 49 steps to reach 1.

LaTeX source of the formulas on this page
\[ 42847 = 7 \times 6121 \]

42847 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors48976
Euler totient φ(n)36720
Square1835865409
Cube78661325179423
Square root206.995169
Digit sum / digital root25 / 7
Collatz steps to 149
Scientific notation4.2847 × 10410^{4}

42847 in other forms

FormValue
In wordsforty-two thousand eight hundred and forty-seven
Binary (base 2)1010011101011111
Octal (base 8)123537
Hexadecimal (base 16)A75F
Base 32011202221
As time42847 seconds = 11 h 54 min 7 s

Is 42847 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 2)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7Yes (42847 ÷ 7 = 6121)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 7)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 7)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 7)A number is divisible by 10 if the last digit is 0.
11No (remainder 2)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 7)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 42847 a prime number?

No. 42847 = 7 × 6121, so it is divisible by 7.

What are the factors of 42847?

1, 7, 6121, 42847.

What is 42847 in binary?

1010011101011111 (hexadecimal A75F, octal 123537).

What is the square root of 42847?

About 206.9952.

Is 42847 divisible by 3?

No. Its digits add up to 25, which is not a multiple of 3.

What is special about the number 42847?

42847 is a semiprime: 7 × 6121, the product of two primes.

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