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The number 42823

42823 is a composite number with 8 divisors. Its prime factorisation is 11 × 17 × 229. Divisors (8): 1, 11, 17, 187, 229, 2519, 3893, 42823.

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How to work it out

  1. 1

    What is special about 42823: a happy number: repeatedly adding the squares of its digits reaches 1.

  2. 2

    42823 is composite. Its prime factorisation is

    42823=11×17×22942823 = 11 \times 17 \times 229
  3. 3

    The divisors add up to 49680; without 42823 itself that is 6857, so 42823 is deficient (6857 is less than 42823). Euler's totient φ(42823) = 36480 numbers up to 42823 share no factor with it.

  4. 4

    The digits of 42823 add up to 19, and repeating that until one digit is left gives the digital root 1. The Collatz sequence (halve if even, else 3n+1) takes 150 steps to reach 1.

LaTeX source of the formulas on this page
\[ 42823 = 11 \times 17 \times 229 \]

42823 at a glance

PropertyValue
Typecomposite
Number of divisors8
Sum of divisors49680
Euler totient φ(n)36480
Square1833809329
Cube78529216895767
Square root206.937189
Digit sum / digital root19 / 1
Collatz steps to 1150
Scientific notation4.2823 × 10410^{4}

42823 in other forms

FormValue
In wordsforty-two thousand eight hundred and twenty-three
Binary (base 2)1010011101000111
Octal (base 8)123507
Hexadecimal (base 16)A747
Base 32011202001
As time42823 seconds = 11 h 53 min 43 s

Is 42823 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 4)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 7)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 1)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11Yes (42823 ÷ 11 = 3893)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 7)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 42823 a prime number?

No. 42823 = 11 × 17 × 229, so it is divisible by 11.

What are the factors of 42823?

1, 11, 17, 187, 229, 2519, 3893, 42823.

What is 42823 in binary?

1010011101000111 (hexadecimal A747, octal 123507).

What is the square root of 42823?

About 206.9372.

Is 42823 divisible by 3?

No. Its digits add up to 19, which is not a multiple of 3.

What is special about the number 42823?

42823 is a happy number: repeatedly adding the squares of its digits reaches 1.

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    42823: is it prime? Factors, square root, binary, Roman numeral | WordGPT