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The number 42631

42631 is a composite number with 4 divisors. Its prime factorisation is 89 × 479. Divisors (4): 1, 89, 479, 42631.

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How to work it out

  1. 1

    What is special about 42631: a semiprime: 89 × 479, the product of two primes.

  2. 2

    42631 is composite. Its prime factorisation is

    42631=89×47942631 = 89 \times 479
  3. 3

    The divisors add up to 43200; without 42631 itself that is 569, so 42631 is deficient (569 is less than 42631). Euler's totient φ(42631) = 42064 numbers up to 42631 share no factor with it.

  4. 4

    The digits of 42631 add up to 16, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 88 steps to reach 1.

LaTeX source of the formulas on this page
\[ 42631 = 89 \times 479 \]

42631 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors43200
Euler totient φ(n)42064
Square1817402161
Cube77477671525591
Square root206.472758
Digit sum / digital root16 / 7
Collatz steps to 188
Scientific notation4.2631 × 10410^{4}

42631 in other forms

FormValue
In wordsforty-two thousand six hundred and thirty-one
Binary (base 2)1010011010000111
Octal (base 8)123207
Hexadecimal (base 16)A687
Base 32011110221
As time42631 seconds = 11 h 50 min 31 s

Is 42631 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 1)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 1)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 7)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 7)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 1)A number is divisible by 10 if the last digit is 0.
11No (remainder 6)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 7)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 42631 a prime number?

No. 42631 = 89 × 479, so it is divisible by 89.

What are the factors of 42631?

1, 89, 479, 42631.

What is 42631 in binary?

1010011010000111 (hexadecimal A687, octal 123207).

What is the square root of 42631?

About 206.4728.

Is 42631 divisible by 3?

No. Its digits add up to 16, which is not a multiple of 3.

What is special about the number 42631?

42631 is a semiprime: 89 × 479, the product of two primes.

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    42631: is it prime? Factors, square root, binary, Roman numeral | WordGPT