The number 42535
42535 is a composite number with 8 divisors. Its prime factorisation is 5 × 47 × 181. Divisors (8): 1, 5, 47, 181, 235, 905, 8507, 42535.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 42535: a happy number: repeatedly adding the squares of its digits reaches 1.
- 2
42535 is composite. Its prime factorisation is
- 3
The divisors add up to 52416; without 42535 itself that is 9881, so 42535 is deficient (9881 is less than 42535). Euler's totient φ(42535) = 33120 numbers up to 42535 share no factor with it.
- 4
The digits of 42535 add up to 19, and repeating that until one digit is left gives the digital root 1. The Collatz sequence (halve if even, else 3n+1) takes 150 steps to reach 1.
LaTeX source of the formulas on this page
\[ 42535 = 5 \times 47 \times 181 \]
42535 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 52416 |
| Euler totient φ(n) | 33120 |
| Square | 1809226225 |
| Cube | 76955437480375 |
| Square root | 206.240151 |
| Digit sum / digital root | 19 / 1 |
| Collatz steps to 1 | 150 |
| Scientific notation | 4.2535 × |
42535 in other forms
| Form | Value |
|---|---|
| In words | forty-two thousand five hundred and thirty-five |
| Binary (base 2) | 1010011000100111 |
| Octal (base 8) | 123047 |
| Hexadecimal (base 16) | A627 |
| Base 3 | 2011100101 |
| As time | 42535 seconds = 11 h 48 min 55 s |
Is 42535 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | Yes (42535 ÷ 5 = 8507) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 3) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 1) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 5) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 9) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 7) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 42535 a prime number?
No. 42535 = 5 × 47 × 181, so it is divisible by 5.
What are the factors of 42535?
1, 5, 47, 181, 235, 905, 8507, 42535.
What is 42535 in binary?
1010011000100111 (hexadecimal A627, octal 123047).
What is the square root of 42535?
About 206.2402.
Is 42535 divisible by 3?
No. Its digits add up to 19, which is not a multiple of 3.
What is special about the number 42535?
42535 is a happy number: repeatedly adding the squares of its digits reaches 1.