The number 42523
42523 is a composite number with 4 divisors. Its prime factorisation is 13 × 3271. Divisors (4): 1, 13, 3271, 42523.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 42523: a semiprime: 13 × 3271, the product of two primes.
- 2
42523 is composite. Its prime factorisation is
- 3
The divisors add up to 45808; without 42523 itself that is 3285, so 42523 is deficient (3285 is less than 42523). Euler's totient φ(42523) = 39240 numbers up to 42523 share no factor with it.
- 4
The digits of 42523 add up to 16, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 62 steps to reach 1.
LaTeX source of the formulas on this page
\[ 42523 = 13 \times 3271 \]
42523 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 45808 |
| Euler totient φ(n) | 39240 |
| Square | 1808205529 |
| Cube | 76890323709667 |
| Square root | 206.211057 |
| Digit sum / digital root | 16 / 7 |
| Collatz steps to 1 | 62 |
| Scientific notation | 4.2523 × |
42523 in other forms
| Form | Value |
|---|---|
| In words | forty-two thousand five hundred and twenty-three |
| Binary (base 2) | 1010011000011011 |
| Octal (base 8) | 123033 |
| Hexadecimal (base 16) | A61B |
| Base 3 | 2011022221 |
| As time | 42523 seconds = 11 h 48 min 43 s |
Is 42523 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 5) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 3) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 7) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 8) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 7) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 42523 a prime number?
No. 42523 = 13 × 3271, so it is divisible by 13.
What are the factors of 42523?
1, 13, 3271, 42523.
What is 42523 in binary?
1010011000011011 (hexadecimal A61B, octal 123033).
What is the square root of 42523?
About 206.2111.
Is 42523 divisible by 3?
No. Its digits add up to 16, which is not a multiple of 3.
What is special about the number 42523?
42523 is a semiprime: 13 × 3271, the product of two primes.