The number 42245
42245 is a composite number with 16 divisors. Its prime factorisation is 5 × 7 × 17 × 71. Divisors (16): 1, 5, 7, 17, 35, 71, 85, 119, 355, 497, 595, 1207, 2485, 6035, 8449, 42245.
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How to work it out
- 1
What is special about 42245: a Harshad number: divisible by its digit sum 17.
- 2
42245 is composite. Its prime factorisation is
- 3
The divisors add up to 62208; without 42245 itself that is 19963, so 42245 is deficient (19963 is less than 42245). Euler's totient φ(42245) = 26880 numbers up to 42245 share no factor with it.
- 4
The digits of 42245 add up to 17, and repeating that until one digit is left gives the digital root 8. The Collatz sequence (halve if even, else 3n+1) takes 57 steps to reach 1.
LaTeX source of the formulas on this page
\[ 42245 = 5 \times 7 \times 17 \times 71 \]
42245 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 16 |
| Sum of divisors | 62208 |
| Euler totient φ(n) | 26880 |
| Square | 1784640025 |
| Cube | 75392117856125 |
| Square root | 205.535885 |
| Digit sum / digital root | 17 / 8 |
| Collatz steps to 1 | 57 |
| Scientific notation | 4.2245 × |
42245 in other forms
| Form | Value |
|---|---|
| In words | forty-two thousand two hundred and forty-five |
| Binary (base 2) | 1010010100000101 |
| Octal (base 8) | 122405 |
| Hexadecimal (base 16) | A505 |
| Base 3 | 2010221122 |
| As time | 42245 seconds = 11 h 44 min 5 s |
Is 42245 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | Yes (42245 ÷ 5 = 8449) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | Yes (42245 ÷ 7 = 6035) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 8) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 5) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 5) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 42245 a prime number?
No. 42245 = 5 × 7 × 17 × 71, so it is divisible by 5.
What are the factors of 42245?
1, 5, 7, 17, 35, 71, 85, 119, 355, 497, 595, 1207, 2485, 6035, 8449, 42245.
What is 42245 in binary?
1010010100000101 (hexadecimal A505, octal 122405).
What is the square root of 42245?
About 205.5359.
Is 42245 divisible by 3?
No. Its digits add up to 17, which is not a multiple of 3.
What is special about the number 42245?
42245 is a Harshad number: divisible by its digit sum 17.