The number 40921
40921 is a composite number with 4 divisors. Its prime factorisation is 151 × 271. Divisors (4): 1, 151, 271, 40921.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 40921: a semiprime: 151 × 271, the product of two primes.
- 2
40921 is composite. Its prime factorisation is
- 3
The divisors add up to 41344; without 40921 itself that is 423, so 40921 is deficient (423 is less than 40921). Euler's totient φ(40921) = 40500 numbers up to 40921 share no factor with it.
- 4
The digits of 40921 add up to 16, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 62 steps to reach 1.
LaTeX source of the formulas on this page
\[ 40921 = 151 \times 271 \]
40921 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 41344 |
| Euler totient φ(n) | 40500 |
| Square | 1674528241 |
| Cube | 68523370149961 |
| Square root | 202.289397 |
| Digit sum / digital root | 16 / 7 |
| Collatz steps to 1 | 62 |
| Scientific notation | 4.0921 × |
40921 in other forms
| Form | Value |
|---|---|
| In words | forty thousand nine hundred and twenty-one |
| Binary (base 2) | 1001111111011001 |
| Octal (base 8) | 117731 |
| Hexadecimal (base 16) | 9FD9 |
| Base 3 | 2002010121 |
| As time | 40921 seconds = 11 h 22 min 1 s |
Is 40921 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 1) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 6) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 7) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 1) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 1) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 1) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 40921 a prime number?
No. 40921 = 151 × 271, so it is divisible by 151.
What are the factors of 40921?
1, 151, 271, 40921.
What is 40921 in binary?
1001111111011001 (hexadecimal 9FD9, octal 117731).
What is the square root of 40921?
About 202.2894.
Is 40921 divisible by 3?
No. Its digits add up to 16, which is not a multiple of 3.
What is special about the number 40921?
40921 is a semiprime: 151 × 271, the product of two primes.