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The number 40723

40723 is a composite number with 4 divisors. Its prime factorisation is 193 × 211. Divisors (4): 1, 193, 211, 40723.

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How to work it out

  1. 1

    What is special about 40723: a semiprime: 193 × 211, the product of two primes.

  2. 2

    40723 is composite. Its prime factorisation is

    40723=193×21140723 = 193 \times 211
  3. 3

    The divisors add up to 41128; without 40723 itself that is 405, so 40723 is deficient (405 is less than 40723). Euler's totient φ(40723) = 40320 numbers up to 40723 share no factor with it.

  4. 4

    The digits of 40723 add up to 16, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 88 steps to reach 1.

LaTeX source of the formulas on this page
\[ 40723 = 193 \times 211 \]

40723 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors41128
Euler totient φ(n)40320
Square1658362729
Cube67533505413067
Square root201.799405
Digit sum / digital root16 / 7
Collatz steps to 188
Scientific notation4.0723 × 10410^{4}

40723 in other forms

FormValue
In wordsforty thousand seven hundred and twenty-three
Binary (base 2)1001111100010011
Octal (base 8)117423
Hexadecimal (base 16)9F13
Base 32001212021
As time40723 seconds = 11 h 18 min 43 s

Is 40723 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 4)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 3)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 7)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 1)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 7)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 40723 a prime number?

No. 40723 = 193 × 211, so it is divisible by 193.

What are the factors of 40723?

1, 193, 211, 40723.

What is 40723 in binary?

1001111100010011 (hexadecimal 9F13, octal 117423).

What is the square root of 40723?

About 201.7994.

Is 40723 divisible by 3?

No. Its digits add up to 16, which is not a multiple of 3.

What is special about the number 40723?

40723 is a semiprime: 193 × 211, the product of two primes.

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