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The number 40631

40631 is a composite number with 4 divisors. Its prime factorisation is 41 × 991. Divisors (4): 1, 41, 991, 40631.

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How to work it out

  1. 1

    What is special about 40631: a semiprime: 41 × 991, the product of two primes.

  2. 2

    40631 is composite. Its prime factorisation is

    40631=41×99140631 = 41 \times 991
  3. 3

    The divisors add up to 41664; without 40631 itself that is 1033, so 40631 is deficient (1033 is less than 40631). Euler's totient φ(40631) = 39600 numbers up to 40631 share no factor with it.

  4. 4

    The digits of 40631 add up to 14, and repeating that until one digit is left gives the digital root 5. The Collatz sequence (halve if even, else 3n+1) takes 93 steps to reach 1.

LaTeX source of the formulas on this page
\[ 40631 = 41 \times 991 \]

40631 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors41664
Euler totient φ(n)39600
Square1650878161
Cube67076830559591
Square root201.571327
Digit sum / digital root14 / 5
Collatz steps to 193
Scientific notation4.0631 × 10410^{4}

40631 in other forms

FormValue
In wordsforty thousand six hundred and thirty-one
Binary (base 2)1001111010110111
Octal (base 8)117267
Hexadecimal (base 16)9EB7
Base 32001201212
As time40631 seconds = 11 h 17 min 11 s

Is 40631 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 2)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 1)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 5)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 3)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 7)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 5)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 1)A number is divisible by 10 if the last digit is 0.
11No (remainder 8)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 11)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 40631 a prime number?

No. 40631 = 41 × 991, so it is divisible by 41.

What are the factors of 40631?

1, 41, 991, 40631.

What is 40631 in binary?

1001111010110111 (hexadecimal 9EB7, octal 117267).

What is the square root of 40631?

About 201.5713.

Is 40631 divisible by 3?

No. Its digits add up to 14, which is not a multiple of 3.

What is special about the number 40631?

40631 is a semiprime: 41 × 991, the product of two primes.

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