The number 40479
40479 is a composite number with 8 divisors. Its prime factorisation is 3 × 103 × 131. Divisors (8): 1, 3, 103, 131, 309, 393, 13493, 40479.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
40479 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
40479 is composite. Its prime factorisation is
- 3
The divisors add up to 54912; without 40479 itself that is 14433, so 40479 is deficient (14433 is less than 40479). Euler's totient φ(40479) = 26520 numbers up to 40479 share no factor with it.
- 4
The digits of 40479 add up to 24, and repeating that until one digit is left gives the digital root 6. The Collatz sequence (halve if even, else 3n+1) takes 150 steps to reach 1.
LaTeX source of the formulas on this page
\[ 40479 = 3 \times 103 \times 131 \]
40479 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 54912 |
| Euler totient φ(n) | 26520 |
| Square | 1638549441 |
| Cube | 66326842822239 |
| Square root | 201.193936 |
| Digit sum / digital root | 24 / 6 |
| Collatz steps to 1 | 150 |
| Scientific notation | 4.0479 × |
40479 in other forms
| Form | Value |
|---|---|
| In words | forty thousand four hundred and seventy-nine |
| Binary (base 2) | 1001111000011111 |
| Octal (base 8) | 117037 |
| Hexadecimal (base 16) | 9E1F |
| Base 3 | 2001112020 |
| As time | 40479 seconds = 11 h 14 min 39 s |
Is 40479 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (40479 ÷ 3 = 13493) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 4) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 5) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 6) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 9) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 10) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 3) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 40479 a prime number?
No. 40479 = 3 × 103 × 131, so it is divisible by 3.
What are the factors of 40479?
1, 3, 103, 131, 309, 393, 13493, 40479.
What is 40479 in binary?
1001111000011111 (hexadecimal 9E1F, octal 117037).
What is the square root of 40479?
About 201.1939.
Is 40479 divisible by 3?
Yes. Its digits add up to 24, a multiple of 3.
What is special about the number 40479?
It is a composite number with 8 divisors.