The number 40403
40403 is a composite number with 4 divisors. Its prime factorisation is 11 × 3673. Divisors (4): 1, 11, 3673, 40403.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 40403: a Harshad number: divisible by its digit sum 11; a semiprime: 11 × 3673, the product of two primes.
- 2
40403 is composite. Its prime factorisation is
- 3
The divisors add up to 44088; without 40403 itself that is 3685, so 40403 is deficient (3685 is less than 40403). Euler's totient φ(40403) = 36720 numbers up to 40403 share no factor with it.
- 4
The digits of 40403 add up to 11, and repeating that until one digit is left gives the digital root 2. The Collatz sequence (halve if even, else 3n+1) takes 88 steps to reach 1.
LaTeX source of the formulas on this page
\[ 40403 = 11 \times 3673 \]
40403 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 44088 |
| Euler totient φ(n) | 36720 |
| Square | 1632402409 |
| Cube | 65953954530827 |
| Square root | 201.004975 |
| Digit sum / digital root | 11 / 2 |
| Collatz steps to 1 | 88 |
| Scientific notation | 4.0403 × |
40403 in other forms
| Form | Value |
|---|---|
| In words | forty thousand four hundred and three |
| Binary (base 2) | 1001110111010011 |
| Octal (base 8) | 116723 |
| Hexadecimal (base 16) | 9DD3 |
| Base 3 | 2001102102 |
| As time | 40403 seconds = 11 h 13 min 23 s |
Is 40403 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 6) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 3) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 2) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | Yes (40403 ÷ 11 = 3673) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 11) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 40403 a prime number?
No. 40403 = 11 × 3673, so it is divisible by 11.
What are the factors of 40403?
1, 11, 3673, 40403.
What is 40403 in binary?
1001110111010011 (hexadecimal 9DD3, octal 116723).
What is the square root of 40403?
About 201.0050.
Is 40403 divisible by 3?
No. Its digits add up to 11, which is not a multiple of 3.
What is special about the number 40403?
40403 is a Harshad number: divisible by its digit sum 11; a semiprime: 11 × 3673, the product of two primes.