The number 4023
4023 is a composite number with 8 divisors. Its prime factorisation is × 149. Divisors (8): 1, 3, 9, 27, 149, 447, 1341, 4023.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 4023: a Harshad number: divisible by its digit sum 9.
- 2
4023 is composite. Its prime factorisation is
- 3
The divisors add up to 6000; without 4023 itself that is 1977, so 4023 is deficient (1977 is less than 4023). Euler's totient φ(4023) = 2664 numbers up to 4023 share no factor with it.
- 4
The digits of 4023 add up to 9, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 43 steps to reach 1.
LaTeX source of the formulas on this page
\[ 4023 = 3^{3} \times 149 \]4023 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 6000 |
| Euler totient φ(n) | 2664 |
| Square | 16184529 |
| Cube | 65110360167 |
| Square root | 63.427124 (= 3√447) |
| Digit sum / digital root | 9 / 9 |
| Collatz steps to 1 | 43 |
| Scientific notation | 4.023 × |
4023 in other forms
| Form | Value |
|---|---|
| In words | four thousand and twenty-three |
| Binary (base 2) | 111110110111 |
| Octal (base 8) | 7667 |
| Hexadecimal (base 16) | FB7 |
| Base 3 | 12112000 |
| As time | 4023 seconds = 1 h 7 min 3 s |
Is 4023 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (4023 ÷ 3 = 1341) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 5) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (4023 ÷ 9 = 447) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 8) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 3) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 4023 a prime number?
No. 4023 = × 149, so it is divisible by 3.
What are the factors of 4023?
1, 3, 9, 27, 149, 447, 1341, 4023.
What is 4023 in binary?
111110110111 (hexadecimal FB7, octal 7667).
What is the square root of 4023?
About 63.4271, exactly 3√447.
Is 4023 divisible by 3?
Yes. Its digits add up to 9, a multiple of 3.
What is special about the number 4023?
4023 is a Harshad number: divisible by its digit sum 9.