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The number 40141

40141 is a composite number with 4 divisors. Its prime factorisation is 137 × 293. Divisors (4): 1, 137, 293, 40141.

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How to work it out

  1. 1

    What is special about 40141: a semiprime: 137 × 293, the product of two primes.

  2. 2

    40141 is composite. Its prime factorisation is

    40141=137×29340141 = 137 \times 293
  3. 3

    The divisors add up to 40572; without 40141 itself that is 431, so 40141 is deficient (431 is less than 40141). Euler's totient φ(40141) = 39712 numbers up to 40141 share no factor with it.

  4. 4

    The digits of 40141 add up to 10, and repeating that until one digit is left gives the digital root 1. The Collatz sequence (halve if even, else 3n+1) takes 44 steps to reach 1.

LaTeX source of the formulas on this page
\[ 40141 = 137 \times 293 \]

40141 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors40572
Euler totient φ(n)39712
Square1611299881
Cube64679188523221
Square root200.352190
Digit sum / digital root10 / 1
Collatz steps to 144
Scientific notation4.0141 × 10410^{4}

40141 in other forms

FormValue
In wordsforty thousand one hundred and forty-one
Binary (base 2)1001110011001101
Octal (base 8)116315
Hexadecimal (base 16)9CCD
Base 32001001201
As time40141 seconds = 11 h 9 min 1 s

Is 40141 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 1)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 3)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 5)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 1)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 1)A number is divisible by 10 if the last digit is 0.
11No (remainder 2)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 1)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 40141 a prime number?

No. 40141 = 137 × 293, so it is divisible by 137.

What are the factors of 40141?

1, 137, 293, 40141.

What is 40141 in binary?

1001110011001101 (hexadecimal 9CCD, octal 116315).

What is the square root of 40141?

About 200.3522.

Is 40141 divisible by 3?

No. Its digits add up to 10, which is not a multiple of 3.

What is special about the number 40141?

40141 is a semiprime: 137 × 293, the product of two primes.

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