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The number 40133

40133 is a composite number with 4 divisors. Its prime factorisation is 67 × 599. Divisors (4): 1, 67, 599, 40133.

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How to work it out

  1. 1

    What is special about 40133: a semiprime: 67 × 599, the product of two primes.

  2. 2

    40133 is composite. Its prime factorisation is

    40133=67×59940133 = 67 \times 599
  3. 3

    The divisors add up to 40800; without 40133 itself that is 667, so 40133 is deficient (667 is less than 40133). Euler's totient φ(40133) = 39468 numbers up to 40133 share no factor with it.

  4. 4

    The digits of 40133 add up to 11, and repeating that until one digit is left gives the digital root 2. The Collatz sequence (halve if even, else 3n+1) takes 44 steps to reach 1.

LaTeX source of the formulas on this page
\[ 40133 = 67 \times 599 \]

40133 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors40800
Euler totient φ(n)39468
Square1610657689
Cube64640525032637
Square root200.332224
Digit sum / digital root11 / 2
Collatz steps to 144
Scientific notation4.0133 × 10410^{4}

40133 in other forms

FormValue
In wordsforty thousand one hundred and thirty-three
Binary (base 2)1001110011000101
Octal (base 8)116305
Hexadecimal (base 16)9CC5
Base 32001001102
As time40133 seconds = 11 h 8 min 53 s

Is 40133 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 2)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 5)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 2)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 5)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 2)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 5)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 5)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 40133 a prime number?

No. 40133 = 67 × 599, so it is divisible by 67.

What are the factors of 40133?

1, 67, 599, 40133.

What is 40133 in binary?

1001110011000101 (hexadecimal 9CC5, octal 116305).

What is the square root of 40133?

About 200.3322.

Is 40133 divisible by 3?

No. Its digits add up to 11, which is not a multiple of 3.

What is special about the number 40133?

40133 is a semiprime: 67 × 599, the product of two primes.

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