The number 36477
36477 is a composite number with 16 divisors. Its prime factorisation is × 7 × 193. Divisors (16): 1, 3, 7, 9, 21, 27, 63, 189, 193, 579, 1351, 1737, 4053, 5211, 12159, 36477.
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How to work it out
- 1
What is special about 36477: a Harshad number: divisible by its digit sum 27.
- 2
36477 is composite. Its prime factorisation is
- 3
The divisors add up to 62080; without 36477 itself that is 25603, so 36477 is deficient (25603 is less than 36477). Euler's totient φ(36477) = 20736 numbers up to 36477 share no factor with it.
- 4
The digits of 36477 add up to 27, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 67 steps to reach 1.
LaTeX source of the formulas on this page
\[ 36477 = 3^{3} \times 7 \times 193 \]36477 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 16 |
| Sum of divisors | 62080 |
| Euler totient φ(n) | 20736 |
| Square | 1330571529 |
| Cube | 48535257663333 |
| Square root | 190.989529 (= 3√4053) |
| Digit sum / digital root | 27 / 9 |
| Collatz steps to 1 | 67 |
| Scientific notation | 3.6477 × |
36477 in other forms
| Form | Value |
|---|---|
| In words | thirty-six thousand four hundred and seventy-seven |
| Binary (base 2) | 1000111001111101 |
| Octal (base 8) | 107175 |
| Hexadecimal (base 16) | 8E7D |
| Base 3 | 1212001000 |
| As time | 36477 seconds = 10 h 7 min 57 s |
Is 36477 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (36477 ÷ 3 = 12159) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 2) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | Yes (36477 ÷ 7 = 5211) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (36477 ÷ 9 = 4053) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 7) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 1) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 9) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 36477 a prime number?
No. 36477 = × 7 × 193, so it is divisible by 3.
What are the factors of 36477?
1, 3, 7, 9, 21, 27, 63, 189, 193, 579, 1351, 1737, 4053, 5211, 12159, 36477.
What is 36477 in binary?
1000111001111101 (hexadecimal 8E7D, octal 107175).
What is the square root of 36477?
About 190.9895, exactly 3√4053.
Is 36477 divisible by 3?
Yes. Its digits add up to 27, a multiple of 3.
What is special about the number 36477?
36477 is a Harshad number: divisible by its digit sum 27.