The number 35397
35397 is a composite number with 20 divisors. Its prime factorisation is × 19 × 23. Divisors (20): 1, 3, 9, 19, 23, 27, 57, 69, 81, 171, 207, 437, 513, 621, 1311, 1539 … 35397.
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How to work it out
- 1
What is special about 35397: a Harshad number: divisible by its digit sum 27.
- 2
35397 is composite. Its prime factorisation is
- 3
The divisors add up to 58080; without 35397 itself that is 22683, so 35397 is deficient (22683 is less than 35397). Euler's totient φ(35397) = 21384 numbers up to 35397 share no factor with it.
- 4
The digits of 35397 add up to 27, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 49 steps to reach 1.
LaTeX source of the formulas on this page
\[ 35397 = 3^{4} \times 19 \times 23 \]35397 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 20 |
| Sum of divisors | 58080 |
| Euler totient φ(n) | 21384 |
| Square | 1252947609 |
| Cube | 44350586515773 |
| Square root | 188.140905 (= 9√437) |
| Digit sum / digital root | 27 / 9 |
| Collatz steps to 1 | 49 |
| Scientific notation | 3.5397 × |
35397 in other forms
| Form | Value |
|---|---|
| In words | thirty-five thousand three hundred and ninety-seven |
| Binary (base 2) | 1000101001000101 |
| Octal (base 8) | 105105 |
| Hexadecimal (base 16) | 8A45 |
| Base 3 | 1210120000 |
| As time | 35397 seconds = 9 h 49 min 57 s |
Is 35397 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (35397 ÷ 3 = 11799) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 2) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 5) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (35397 ÷ 9 = 3933) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 7) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 10) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 9) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 35397 a prime number?
No. 35397 = × 19 × 23, so it is divisible by 3.
What are the factors of 35397?
1, 3, 9, 19, 23, 27, 57, 69, 81, 171, 207, 437, 513, 621, 1311, 1539, 1863, 3933, 11799, 35397.
What is 35397 in binary?
1000101001000101 (hexadecimal 8A45, octal 105105).
What is the square root of 35397?
About 188.1409, exactly 9√437.
Is 35397 divisible by 3?
Yes. Its digits add up to 27, a multiple of 3.
What is special about the number 35397?
35397 is a Harshad number: divisible by its digit sum 27.