The number 3423
3423 is a composite number with 8 divisors. Its prime factorisation is 3 × 7 × 163. Divisors (8): 1, 3, 7, 21, 163, 489, 1141, 3423.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
3423 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
3423 is composite. Its prime factorisation is
- 3
The divisors add up to 5248; without 3423 itself that is 1825, so 3423 is deficient (1825 is less than 3423). Euler's totient φ(3423) = 1944 numbers up to 3423 share no factor with it.
- 4
The digits of 3423 add up to 12, and repeating that until one digit is left gives the digital root 3. The Collatz sequence (halve if even, else 3n+1) takes 149 steps to reach 1.
LaTeX source of the formulas on this page
\[ 3423 = 3 \times 7 \times 163 \]
3423 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 5248 |
| Euler totient φ(n) | 1944 |
| Square | 11716929 |
| Cube | 40107047967 |
| Square root | 58.506410 |
| Digit sum / digital root | 12 / 3 |
| Collatz steps to 1 | 149 |
| Scientific notation | 3.423 × |
3423 in other forms
| Form | Value |
|---|---|
| In words | three thousand four hundred and twenty-three |
| Roman numerals | MMMCDXXIII |
| Binary (base 2) | 110101011111 |
| Octal (base 8) | 6537 |
| Hexadecimal (base 16) | D5F |
| Base 3 | 11200210 |
| As time | 3423 seconds = 57 min 3 s |
Is 3423 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (3423 ÷ 3 = 1141) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | Yes (3423 ÷ 7 = 489) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 3) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 2) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 3) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 3423 a prime number?
No. 3423 = 3 × 7 × 163, so it is divisible by 3.
What are the factors of 3423?
1, 3, 7, 21, 163, 489, 1141, 3423.
What is 3423 in binary?
110101011111 (hexadecimal D5F, octal 6537).
What is the square root of 3423?
About 58.5064.
What is 3423 in Roman numerals?
MMMCDXXIII.
Is 3423 divisible by 3?
Yes. Its digits add up to 12, a multiple of 3.
What is special about the number 3423?
It is a composite number with 8 divisors.