The number 34121
34121 is a composite number with 4 divisors. Its prime factorisation is 149 × 229. Divisors (4): 1, 149, 229, 34121.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 34121: a happy number: repeatedly adding the squares of its digits reaches 1; a semiprime: 149 × 229, the product of two primes.
- 2
34121 is composite. Its prime factorisation is
- 3
The divisors add up to 34500; without 34121 itself that is 379, so 34121 is deficient (379 is less than 34121). Euler's totient φ(34121) = 33744 numbers up to 34121 share no factor with it.
- 4
The digits of 34121 add up to 11, and repeating that until one digit is left gives the digital root 2. The Collatz sequence (halve if even, else 3n+1) takes 80 steps to reach 1.
LaTeX source of the formulas on this page
\[ 34121 = 149 \times 229 \]
34121 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 34500 |
| Euler totient φ(n) | 33744 |
| Square | 1164242641 |
| Cube | 39725123153561 |
| Square root | 184.718705 |
| Digit sum / digital root | 11 / 2 |
| Collatz steps to 1 | 80 |
| Scientific notation | 3.4121 × |
34121 in other forms
| Form | Value |
|---|---|
| In words | thirty-four thousand one hundred and twenty-one |
| Binary (base 2) | 1000010101001001 |
| Octal (base 8) | 102511 |
| Hexadecimal (base 16) | 8549 |
| Base 3 | 1201210202 |
| As time | 34121 seconds = 9 h 28 min 41 s |
Is 34121 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 1) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 3) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 2) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 1) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 10) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 34121 a prime number?
No. 34121 = 149 × 229, so it is divisible by 149.
What are the factors of 34121?
1, 149, 229, 34121.
What is 34121 in binary?
1000010101001001 (hexadecimal 8549, octal 102511).
What is the square root of 34121?
About 184.7187.
Is 34121 divisible by 3?
No. Its digits add up to 11, which is not a multiple of 3.
What is special about the number 34121?
34121 is a happy number: repeatedly adding the squares of its digits reaches 1; a semiprime: 149 × 229, the product of two primes.