The number 32513
32513 is a composite number with 8 divisors. Its prime factorisation is 13 × 41 × 61. Divisors (8): 1, 13, 41, 61, 533, 793, 2501, 32513.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
32513 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
32513 is composite. Its prime factorisation is
- 3
The divisors add up to 36456; without 32513 itself that is 3943, so 32513 is deficient (3943 is less than 32513). Euler's totient φ(32513) = 28800 numbers up to 32513 share no factor with it.
- 4
The digits of 32513 add up to 14, and repeating that until one digit is left gives the digital root 5. The Collatz sequence (halve if even, else 3n+1) takes 41 steps to reach 1.
LaTeX source of the formulas on this page
\[ 32513 = 13 \times 41 \times 61 \]
32513 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 36456 |
| Euler totient φ(n) | 28800 |
| Square | 1057095169 |
| Cube | 34369335229697 |
| Square root | 180.313616 |
| Digit sum / digital root | 14 / 5 |
| Collatz steps to 1 | 41 |
| Scientific notation | 3.2513 × |
32513 in other forms
| Form | Value |
|---|---|
| In words | thirty-two thousand five hundred and thirteen |
| Binary (base 2) | 111111100000001 |
| Octal (base 8) | 77401 |
| Hexadecimal (base 16) | 7F01 |
| Base 3 | 1122121012 |
| As time | 32513 seconds = 9 h 1 min 53 s |
Is 32513 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 5) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 5) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 8) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 32513 a prime number?
No. 32513 = 13 × 41 × 61, so it is divisible by 13.
What are the factors of 32513?
1, 13, 41, 61, 533, 793, 2501, 32513.
What is 32513 in binary?
111111100000001 (hexadecimal 7F01, octal 77401).
What is the square root of 32513?
About 180.3136.
Is 32513 divisible by 3?
No. Its digits add up to 14, which is not a multiple of 3.
What is special about the number 32513?
It is a composite number with 8 divisors.