The number 32489
32489 is a composite number with 4 divisors. Its prime factorisation is 53 × 613. Divisors (4): 1, 53, 613, 32489.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 32489: a semiprime: 53 × 613, the product of two primes.
- 2
32489 is composite. Its prime factorisation is
- 3
The divisors add up to 33156; without 32489 itself that is 667, so 32489 is deficient (667 is less than 32489). Euler's totient φ(32489) = 31824 numbers up to 32489 share no factor with it.
- 4
The digits of 32489 add up to 26, and repeating that until one digit is left gives the digital root 8. The Collatz sequence (halve if even, else 3n+1) takes 67 steps to reach 1.
LaTeX source of the formulas on this page
\[ 32489 = 53 \times 613 \]
32489 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 33156 |
| Euler totient φ(n) | 31824 |
| Square | 1055535121 |
| Cube | 34293280546169 |
| Square root | 180.247053 |
| Digit sum / digital root | 26 / 8 |
| Collatz steps to 1 | 67 |
| Scientific notation | 3.2489 × |
32489 in other forms
| Form | Value |
|---|---|
| In words | thirty-two thousand four hundred and eighty-nine |
| Binary (base 2) | 111111011101001 |
| Octal (base 8) | 77351 |
| Hexadecimal (base 16) | 7EE9 |
| Base 3 | 1122120022 |
| As time | 32489 seconds = 9 h 1 min 29 s |
Is 32489 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 4) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 2) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 8) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 9) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 6) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 32489 a prime number?
No. 32489 = 53 × 613, so it is divisible by 53.
What are the factors of 32489?
1, 53, 613, 32489.
What is 32489 in binary?
111111011101001 (hexadecimal 7EE9, octal 77351).
What is the square root of 32489?
About 180.2471.
Is 32489 divisible by 3?
No. Its digits add up to 26, which is not a multiple of 3.
What is special about the number 32489?
32489 is a semiprime: 53 × 613, the product of two primes.