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The number 32426

32426 is a composite number with 8 divisors. Its prime factorisation is 2 × 31 × 523. Divisors (8): 1, 2, 31, 62, 523, 1046, 16213, 32426.

Number

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How to work it out

  1. 1

    32426 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.

  2. 2

    32426 is composite. Its prime factorisation is

    32426=2×31×52332426 = 2 \times 31 \times 523
  3. 3

    The divisors add up to 50304; without 32426 itself that is 17878, so 32426 is deficient (17878 is less than 32426). Euler's totient φ(32426) = 15660 numbers up to 32426 share no factor with it.

  4. 4

    The digits of 32426 add up to 17, and repeating that until one digit is left gives the digital root 8. The Collatz sequence (halve if even, else 3n+1) takes 116 steps to reach 1.

LaTeX source of the formulas on this page
\[ 32426 = 2 \times 31 \times 523 \]

32426 at a glance

PropertyValue
Typecomposite
Number of divisors8
Sum of divisors50304
Euler totient φ(n)15660
Square1051445476
Cube34094171004776
Square root180.072208
Digit sum / digital root17 / 8
Collatz steps to 1116
Scientific notation3.2426 × 10410^{4}

32426 in other forms

FormValue
In wordsthirty-two thousand four hundred and twenty-six
Binary (base 2)111111010101010
Octal (base 8)77252
Hexadecimal (base 16)7EAA
Base 31122110222
As time32426 seconds = 9 h 0 min 26 s

Is 32426 divisible by 2 to 12?

DivisorAnswerRule
2Yes (32426 ÷ 2 = 16213)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 2)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 2)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 1)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 2)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 2)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 2)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 8)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 6)A number is divisible by 10 if the last digit is 0.
11No (remainder 9)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 2)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 32426 a prime number?

No. 32426 = 2 × 31 × 523, so it is divisible by 2.

What are the factors of 32426?

1, 2, 31, 62, 523, 1046, 16213, 32426.

What is 32426 in binary?

111111010101010 (hexadecimal 7EAA, octal 77252).

What is the square root of 32426?

About 180.0722.

Is 32426 divisible by 3?

No. Its digits add up to 17, which is not a multiple of 3.

What is special about the number 32426?

It is a composite number with 8 divisors.

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