The number 32243
32243 is a composite number with 4 divisors. Its prime factorisation is 19 × 1697. Divisors (4): 1, 19, 1697, 32243.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 32243: a semiprime: 19 × 1697, the product of two primes.
- 2
32243 is composite. Its prime factorisation is
- 3
The divisors add up to 33960; without 32243 itself that is 1717, so 32243 is deficient (1717 is less than 32243). Euler's totient φ(32243) = 30528 numbers up to 32243 share no factor with it.
- 4
The digits of 32243 add up to 14, and repeating that until one digit is left gives the digital root 5. The Collatz sequence (halve if even, else 3n+1) takes 98 steps to reach 1.
LaTeX source of the formulas on this page
\[ 32243 = 19 \times 1697 \]
32243 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 33960 |
| Euler totient φ(n) | 30528 |
| Square | 1039611049 |
| Cube | 33520179052907 |
| Square root | 179.563359 |
| Digit sum / digital root | 14 / 5 |
| Collatz steps to 1 | 98 |
| Scientific notation | 3.2243 × |
32243 in other forms
| Form | Value |
|---|---|
| In words | thirty-two thousand two hundred and forty-three |
| Binary (base 2) | 111110111110011 |
| Octal (base 8) | 76763 |
| Hexadecimal (base 16) | 7DF3 |
| Base 3 | 1122020012 |
| As time | 32243 seconds = 8 h 57 min 23 s |
Is 32243 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 1) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 3) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 5) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 2) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 11) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 32243 a prime number?
No. 32243 = 19 × 1697, so it is divisible by 19.
What are the factors of 32243?
1, 19, 1697, 32243.
What is 32243 in binary?
111110111110011 (hexadecimal 7DF3, octal 76763).
What is the square root of 32243?
About 179.5634.
Is 32243 divisible by 3?
No. Its digits add up to 14, which is not a multiple of 3.
What is special about the number 32243?
32243 is a semiprime: 19 × 1697, the product of two primes.