The number 29493
29493 is a composite number with 12 divisors. Its prime factorisation is × 29 × 113. Divisors (12): 1, 3, 9, 29, 87, 113, 261, 339, 1017, 3277, 9831, 29493.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
29493 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
29493 is composite. Its prime factorisation is
- 3
The divisors add up to 44460; without 29493 itself that is 14967, so 29493 is deficient (14967 is less than 29493). Euler's totient φ(29493) = 18816 numbers up to 29493 share no factor with it.
- 4
The digits of 29493 add up to 27, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 134 steps to reach 1.
LaTeX source of the formulas on this page
\[ 29493 = 3^{2} \times 29 \times 113 \]29493 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 12 |
| Sum of divisors | 44460 |
| Euler totient φ(n) | 18816 |
| Square | 869837049 |
| Cube | 25654104086157 |
| Square root | 171.735261 (= 3√3277) |
| Digit sum / digital root | 27 / 9 |
| Collatz steps to 1 | 134 |
| Scientific notation | 2.9493 × |
29493 in other forms
| Form | Value |
|---|---|
| In words | twenty-nine thousand four hundred and ninety-three |
| Binary (base 2) | 111001100110101 |
| Octal (base 8) | 71465 |
| Hexadecimal (base 16) | 7335 |
| Base 3 | 1111110100 |
| As time | 29493 seconds = 8 h 11 min 33 s |
Is 29493 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (29493 ÷ 3 = 9831) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 2) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (29493 ÷ 9 = 3277) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 2) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 9) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 29493 a prime number?
No. 29493 = × 29 × 113, so it is divisible by 3.
What are the factors of 29493?
1, 3, 9, 29, 87, 113, 261, 339, 1017, 3277, 9831, 29493.
What is 29493 in binary?
111001100110101 (hexadecimal 7335, octal 71465).
What is the square root of 29493?
About 171.7353, exactly 3√3277.
Is 29493 divisible by 3?
Yes. Its digits add up to 27, a multiple of 3.
What is special about the number 29493?
It is a composite number with 12 divisors.