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The number 28408

28408 is a composite number with 16 divisors. Its prime factorisation is 232^{3} × 53 × 67. Divisors (16): 1, 2, 4, 8, 53, 67, 106, 134, 212, 268, 424, 536, 3551, 7102, 14204, 28408.

Number

Pick any whole number from 1 to 100,000.

How to work it out

  1. 1

    28408 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.

  2. 2

    28408 is composite. Its prime factorisation is

    28408=23×53×6728408 = 2^{3} \times 53 \times 67
  3. 3

    The divisors add up to 55080; without 28408 itself that is 26672, so 28408 is deficient (26672 is less than 28408). Euler's totient φ(28408) = 13728 numbers up to 28408 share no factor with it.

  4. 4

    The digits of 28408 add up to 22, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 90 steps to reach 1.

LaTeX source of the formulas on this page
\[ 28408 = 2^{3} \times 53 \times 67 \]

28408 at a glance

PropertyValue
Typecomposite
Number of divisors16
Sum of divisors55080
Euler totient φ(n)13728
Square807014464
Cube22925666893312
Square root168.546729 (= 2√7102)
Digit sum / digital root22 / 4
Collatz steps to 190
Scientific notation2.8408 × 10410^{4}

28408 in other forms

FormValue
In wordstwenty-eight thousand four hundred and eight
Binary (base 2)110111011111000
Octal (base 8)67370
Hexadecimal (base 16)6EF8
Base 31102222011
As time28408 seconds = 7 h 53 min 28 s

Is 28408 divisible by 2 to 12?

DivisorAnswerRule
2Yes (28408 ÷ 2 = 14204)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4Yes (28408 ÷ 4 = 7102)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 4)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 2)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8Yes (28408 ÷ 8 = 3551)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 4)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 8)A number is divisible by 10 if the last digit is 0.
11No (remainder 6)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 4)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 28408 a prime number?

No. 28408 = 232^{3} × 53 × 67, so it is divisible by 2.

What are the factors of 28408?

1, 2, 4, 8, 53, 67, 106, 134, 212, 268, 424, 536, 3551, 7102, 14204, 28408.

What is 28408 in binary?

110111011111000 (hexadecimal 6EF8, octal 67370).

What is the square root of 28408?

About 168.5467, exactly 2√7102.

Is 28408 divisible by 3?

No. Its digits add up to 22, which is not a multiple of 3.

What is special about the number 28408?

It is a composite number with 16 divisors.

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    28408: is it prime? Factors, square root, binary, Roman numeral | WordGPT