The number 27497
27497 is a composite number with 4 divisors. Its prime factorisation is 31 × 887. Divisors (4): 1, 31, 887, 27497.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 27497: a semiprime: 31 × 887, the product of two primes.
- 2
27497 is composite. Its prime factorisation is
- 3
The divisors add up to 28416; without 27497 itself that is 919, so 27497 is deficient (919 is less than 27497). Euler's totient φ(27497) = 26580 numbers up to 27497 share no factor with it.
- 4
The digits of 27497 add up to 29, and repeating that until one digit is left gives the digital root 2. The Collatz sequence (halve if even, else 3n+1) takes 90 steps to reach 1.
LaTeX source of the formulas on this page
\[ 27497 = 31 \times 887 \]
27497 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 28416 |
| Euler totient φ(n) | 26580 |
| Square | 756085009 |
| Cube | 20790069492473 |
| Square root | 165.822194 |
| Digit sum / digital root | 29 / 2 |
| Collatz steps to 1 | 90 |
| Scientific notation | 2.7497 × |
27497 in other forms
| Form | Value |
|---|---|
| In words | twenty-seven thousand four hundred and ninety-seven |
| Binary (base 2) | 110101101101001 |
| Octal (base 8) | 65551 |
| Hexadecimal (base 16) | 6B69 |
| Base 3 | 1101201102 |
| As time | 27497 seconds = 7 h 38 min 17 s |
Is 27497 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 2) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 1) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 2) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 7) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 8) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 27497 a prime number?
No. 27497 = 31 × 887, so it is divisible by 31.
What are the factors of 27497?
1, 31, 887, 27497.
What is 27497 in binary?
110101101101001 (hexadecimal 6B69, octal 65551).
What is the square root of 27497?
About 165.8222.
Is 27497 divisible by 3?
No. Its digits add up to 29, which is not a multiple of 3.
What is special about the number 27497?
27497 is a semiprime: 31 × 887, the product of two primes.