The number 27423
27423 is a composite number with 12 divisors. Its prime factorisation is × 11 × 277. Divisors (12): 1, 3, 9, 11, 33, 99, 277, 831, 2493, 3047, 9141, 27423.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 27423: a happy number: repeatedly adding the squares of its digits reaches 1.
- 2
27423 is composite. Its prime factorisation is
- 3
The divisors add up to 43368; without 27423 itself that is 15945, so 27423 is deficient (15945 is less than 27423). Euler's totient φ(27423) = 16560 numbers up to 27423 share no factor with it.
- 4
The digits of 27423 add up to 18, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 139 steps to reach 1.
LaTeX source of the formulas on this page
\[ 27423 = 3^{2} \times 11 \times 277 \]27423 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 12 |
| Sum of divisors | 43368 |
| Euler totient φ(n) | 16560 |
| Square | 752020929 |
| Cube | 20622669935967 |
| Square root | 165.598913 (= 3√3047) |
| Digit sum / digital root | 18 / 9 |
| Collatz steps to 1 | 139 |
| Scientific notation | 2.7423 × |
27423 in other forms
| Form | Value |
|---|---|
| In words | twenty-seven thousand four hundred and twenty-three |
| Binary (base 2) | 110101100011111 |
| Octal (base 8) | 65437 |
| Hexadecimal (base 16) | 6B1F |
| Base 3 | 1101121200 |
| As time | 27423 seconds = 7 h 37 min 3 s |
Is 27423 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (27423 ÷ 3 = 9141) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 4) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (27423 ÷ 9 = 3047) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | Yes (27423 ÷ 11 = 2493) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 3) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 27423 a prime number?
No. 27423 = × 11 × 277, so it is divisible by 3.
What are the factors of 27423?
1, 3, 9, 11, 33, 99, 277, 831, 2493, 3047, 9141, 27423.
What is 27423 in binary?
110101100011111 (hexadecimal 6B1F, octal 65437).
What is the square root of 27423?
About 165.5989, exactly 3√3047.
Is 27423 divisible by 3?
Yes. Its digits add up to 18, a multiple of 3.
What is special about the number 27423?
27423 is a happy number: repeatedly adding the squares of its digits reaches 1.