The number 27391
27391 is a composite number with 12 divisors. Its prime factorisation is × 13 × 43. Divisors (12): 1, 7, 13, 43, 49, 91, 301, 559, 637, 2107, 3913, 27391.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
27391 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
27391 is composite. Its prime factorisation is
- 3
The divisors add up to 35112; without 27391 itself that is 7721, so 27391 is deficient (7721 is less than 27391). Euler's totient φ(27391) = 21168 numbers up to 27391 share no factor with it.
- 4
The digits of 27391 add up to 22, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 183 steps to reach 1.
LaTeX source of the formulas on this page
\[ 27391 = 7^{2} \times 13 \times 43 \]27391 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 12 |
| Sum of divisors | 35112 |
| Euler totient φ(n) | 21168 |
| Square | 750266881 |
| Cube | 20550560137471 |
| Square root | 165.502266 (= 7√559) |
| Digit sum / digital root | 22 / 4 |
| Collatz steps to 1 | 183 |
| Scientific notation | 2.7391 × |
27391 in other forms
| Form | Value |
|---|---|
| In words | twenty-seven thousand three hundred and ninety-one |
| Binary (base 2) | 110101011111111 |
| Octal (base 8) | 65377 |
| Hexadecimal (base 16) | 6AFF |
| Base 3 | 1101120111 |
| As time | 27391 seconds = 7 h 36 min 31 s |
Is 27391 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 1) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | Yes (27391 ÷ 7 = 3913) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 4) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 1) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 1) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 7) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 27391 a prime number?
No. 27391 = × 13 × 43, so it is divisible by 7.
What are the factors of 27391?
1, 7, 13, 43, 49, 91, 301, 559, 637, 2107, 3913, 27391.
What is 27391 in binary?
110101011111111 (hexadecimal 6AFF, octal 65377).
What is the square root of 27391?
About 165.5023, exactly 7√559.
Is 27391 divisible by 3?
No. Its digits add up to 22, which is not a multiple of 3.
What is special about the number 27391?
It is a composite number with 12 divisors.