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The number 26773

26773 is a composite number with 4 divisors. Its prime factorisation is 41 × 653. Divisors (4): 1, 41, 653, 26773.

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How to work it out

  1. 1

    What is special about 26773: a semiprime: 41 × 653, the product of two primes.

  2. 2

    26773 is composite. Its prime factorisation is

    26773=41×65326773 = 41 \times 653
  3. 3

    The divisors add up to 27468; without 26773 itself that is 695, so 26773 is deficient (695 is less than 26773). Euler's totient φ(26773) = 26080 numbers up to 26773 share no factor with it.

  4. 4

    The digits of 26773 add up to 25, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 95 steps to reach 1.

LaTeX source of the formulas on this page
\[ 26773 = 41 \times 653 \]

26773 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors27468
Euler totient φ(n)26080
Square716793529
Cube19190713151917
Square root163.624570
Digit sum / digital root25 / 7
Collatz steps to 195
Scientific notation2.6773 × 10410^{4}

26773 in other forms

FormValue
In wordstwenty-six thousand seven hundred and seventy-three
Binary (base 2)110100010010101
Octal (base 8)64225
Hexadecimal (base 16)6895
Base 31100201121
As time26773 seconds = 7 h 26 min 13 s

Is 26773 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 5)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 5)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 7)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 10)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 1)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 26773 a prime number?

No. 26773 = 41 × 653, so it is divisible by 41.

What are the factors of 26773?

1, 41, 653, 26773.

What is 26773 in binary?

110100010010101 (hexadecimal 6895, octal 64225).

What is the square root of 26773?

About 163.6246.

Is 26773 divisible by 3?

No. Its digits add up to 25, which is not a multiple of 3.

What is special about the number 26773?

26773 is a semiprime: 41 × 653, the product of two primes.

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