The number 26520

Q: Is 26520 a prime number?

No. 26520 = 2^3 × 3 × 5 × 13 × 17, so it is divisible by 2.

26520 is a composite number with 64 divisors. Its prime factorisation is $2^{3}$ × 3 × 5 × 13 × 17. Divisors (64): 1, 2, 3, 4, 5, 6, 8, 10, 12, 13, 15, 17, 20, 24, 26, 30 … 26520.

Number

Pick any whole number from 1 to 100,000.

26520 = 2^{3} \times 3 \times 5 \times 13 \times 17

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How to work it out

1
What is special about 26520: a Harshad number: divisible by its digit sum 15.
2
26520 is composite. Its prime factorisation is
$26520 = 2^{3} \times 3 \times 5 \times 13 \times 17$
3
The divisors add up to 90720; without 26520 itself that is 64200, so 26520 is abundant (64200 is more than 26520). Euler's totient φ(26520) = 6144 numbers up to 26520 share no factor with it.
4
The digits of 26520 add up to 15, and repeating that until one digit is left gives the digital root 6. The Collatz sequence (halve if even, else 3n+1) takes 77 steps to reach 1.

LaTeX source of the formulas on this page

\[ 26520 = 2^{3} \times 3 \times 5 \times 13 \times 17 \]

26520 at a glance

Property	Value
Type	composite
Number of divisors	64
Sum of divisors	90720
Euler totient φ(n)	6144
Square	703310400
Cube	18651791808000
Square root	162.849624 (= 2√6630)
Digit sum / digital root	15 / 6
Collatz steps to 1	77
Scientific notation	2.652 × $10^{4}$

26520 in other forms

Form	Value
In words	twenty-six thousand five hundred and twenty
Binary (base 2)	110011110011000
Octal (base 8)	63630
Hexadecimal (base 16)	6798
Base 3	1100101020
As time	26520 seconds = 7 h 22 min 0 s

Is 26520 divisible by 2 to 12?

Divisor	Answer	Rule
2	Yes (26520 ÷ 2 = 13260)	A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3	Yes (26520 ÷ 3 = 8840)	A number is divisible by 3 if the digits add up to a multiple of 3.
4	Yes (26520 ÷ 4 = 6630)	A number is divisible by 4 if the last two digits make a multiple of 4.
5	Yes (26520 ÷ 5 = 5304)	A number is divisible by 5 if the last digit is 0 or 5.
6	Yes (26520 ÷ 6 = 4420)	A number is divisible by 6 if it is divisible by both 2 and 3.
7	No (remainder 4)	A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8	Yes (26520 ÷ 8 = 3315)	A number is divisible by 8 if the last three digits make a multiple of 8.
9	No (remainder 6)	A number is divisible by 9 if the digits add up to a multiple of 9.
10	Yes (26520 ÷ 10 = 2652)	A number is divisible by 10 if the last digit is 0.
11	No (remainder 10)	A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12	Yes (26520 ÷ 12 = 2210)	A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 26520 a prime number?

No. 26520 = $2^{3}$ × 3 × 5 × 13 × 17, so it is divisible by 2.

What are the factors of 26520?

1, 2, 3, 4, 5, 6, 8, 10, 12, 13, 15, 17, 20, 24, 26, 30, 34, 39, 40, 51, 52, 60, 65, 68, 78, 85, 102, 104, 120, 130, 136, 156, 170, 195, 204, 221, 255, 260, 312, 340, 390, 408, 442, 510, 520, 663, 680, 780, 884, 1020, 1105, 1326, 1560, 1768, 2040, 2210, 2652, 3315, 4420, 5304, 6630, 8840, 13260, 26520.

What is 26520 in binary?

110011110011000 (hexadecimal 6798, octal 63630).

What is the square root of 26520?

About 162.8496, exactly 2√6630.

Is 26520 divisible by 3?

Yes. Its digits add up to 15, a multiple of 3.

What is special about the number 26520?

26520 is a Harshad number: divisible by its digit sum 15.