The number 26509
26509 is a composite number with 6 divisors. Its prime factorisation is Ć 541. Divisors (6): 1, 7, 49, 541, 3787, 26509.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
26509 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
26509 is composite. Its prime factorisation is
- 3
The divisors add up to 30894; without 26509 itself that is 4385, so 26509 is deficient (4385 is less than 26509). Euler's totient Ļ(26509) = 22680 numbers up to 26509 share no factor with it.
- 4
The digits of 26509 add up to 22, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 95 steps to reach 1.
LaTeX source of the formulas on this page
\[ 26509 = 7^{2} \times 541 \]26509 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 6 |
| Sum of divisors | 30894 |
| Euler totient Ļ(n) | 22680 |
| Square | 702727081 |
| Cube | 18628592190229 |
| Square root | 162.815847 (= 7ā541) |
| Digit sum / digital root | 22 / 4 |
| Collatz steps to 1 | 95 |
| Scientific notation | 2.6509 Ć |
26509 in other forms
| Form | Value |
|---|---|
| In words | twenty-six thousand five hundred and nine |
| Binary (base 2) | 110011110001101 |
| Octal (base 8) | 63615 |
| Hexadecimal (base 16) | 678D |
| Base 3 | 1100100211 |
| As time | 26509 seconds = 7 h 21 min 49 s |
Is 26509 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 4) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | Yes (26509 Ć· 7 = 3787) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 4) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 9) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 10) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 1) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 26509 a prime number?
No. 26509 = Ć 541, so it is divisible by 7.
What are the factors of 26509?
1, 7, 49, 541, 3787, 26509.
What is 26509 in binary?
110011110001101 (hexadecimal 678D, octal 63615).
What is the square root of 26509?
About 162.8158, exactly 7ā541.
Is 26509 divisible by 3?
No. Its digits add up to 22, which is not a multiple of 3.
What is special about the number 26509?
It is a composite number with 6 divisors.