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The number 26498

26498 is a composite number with 4 divisors. Its prime factorisation is 2 × 13249. Divisors (4): 1, 2, 13249, 26498.

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How to work it out

  1. 1

    What is special about 26498: a semiprime: 2 × 13249, the product of two primes.

  2. 2

    26498 is composite. Its prime factorisation is

    26498=2×1324926498 = 2 \times 13249
  3. 3

    The divisors add up to 39750; without 26498 itself that is 13252, so 26498 is deficient (13252 is less than 26498). Euler's totient φ(26498) = 13248 numbers up to 26498 share no factor with it.

  4. 4

    The digits of 26498 add up to 29, and repeating that until one digit is left gives the digital root 2. The Collatz sequence (halve if even, else 3n+1) takes 77 steps to reach 1.

LaTeX source of the formulas on this page
\[ 26498 = 2 \times 13249 \]

26498 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors39750
Euler totient φ(n)13248
Square702144004
Cube18605411817992
Square root162.782063
Digit sum / digital root29 / 2
Collatz steps to 177
Scientific notation2.6498 × 10410^{4}

26498 in other forms

FormValue
In wordstwenty-six thousand four hundred and ninety-eight
Binary (base 2)110011110000010
Octal (base 8)63602
Hexadecimal (base 16)6782
Base 31100100102
As time26498 seconds = 7 h 21 min 38 s

Is 26498 divisible by 2 to 12?

DivisorAnswerRule
2Yes (26498 ÷ 2 = 13249)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 2)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 2)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 2)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 3)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 2)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 2)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 8)A number is divisible by 10 if the last digit is 0.
11No (remainder 10)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 2)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 26498 a prime number?

No. 26498 = 2 × 13249, so it is divisible by 2.

What are the factors of 26498?

1, 2, 13249, 26498.

What is 26498 in binary?

110011110000010 (hexadecimal 6782, octal 63602).

What is the square root of 26498?

About 162.7821.

Is 26498 divisible by 3?

No. Its digits add up to 29, which is not a multiple of 3.

What is special about the number 26498?

26498 is a semiprime: 2 × 13249, the product of two primes.

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