WordGPT

The number 26487

26487 is a composite number with 12 divisors. Its prime factorisation is 353^{5} × 109. Divisors (12): 1, 3, 9, 27, 81, 109, 243, 327, 981, 2943, 8829, 26487.

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How to work it out

  1. 1

    What is special about 26487: a Harshad number: divisible by its digit sum 27.

  2. 2

    26487 is composite. Its prime factorisation is

    26487=35×10926487 = 3^{5} \times 109
  3. 3

    The divisors add up to 40040; without 26487 itself that is 13553, so 26487 is deficient (13553 is less than 26487). Euler's totient φ(26487) = 17496 numbers up to 26487 share no factor with it.

  4. 4

    The digits of 26487 add up to 27, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 121 steps to reach 1.

LaTeX source of the formulas on this page
\[ 26487 = 3^{5} \times 109 \]

26487 at a glance

PropertyValue
Typecomposite
Number of divisors12
Sum of divisors40040
Euler totient φ(n)17496
Square701561169
Cube18582250683303
Square root162.748272 (= 9√327)
Digit sum / digital root27 / 9
Collatz steps to 1121
Scientific notation2.6487 × 10410^{4}

26487 in other forms

FormValue
In wordstwenty-six thousand four hundred and eighty-seven
Binary (base 2)110011101110111
Octal (base 8)63567
Hexadecimal (base 16)6777
Base 31100100000
As time26487 seconds = 7 h 21 min 27 s

Is 26487 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3Yes (26487 ÷ 3 = 8829)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 2)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 3)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 6)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 7)A number is divisible by 8 if the last three digits make a multiple of 8.
9Yes (26487 ÷ 9 = 2943)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 7)A number is divisible by 10 if the last digit is 0.
11No (remainder 10)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 3)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 26487 a prime number?

No. 26487 = 353^{5} × 109, so it is divisible by 3.

What are the factors of 26487?

1, 3, 9, 27, 81, 109, 243, 327, 981, 2943, 8829, 26487.

What is 26487 in binary?

110011101110111 (hexadecimal 6777, octal 63567).

What is the square root of 26487?

About 162.7483, exactly 9√327.

Is 26487 divisible by 3?

Yes. Its digits add up to 27, a multiple of 3.

What is special about the number 26487?

26487 is a Harshad number: divisible by its digit sum 27.

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