The number 26104
26104 is a composite number with 16 divisors. Its prime factorisation is × 13 × 251. Divisors (16): 1, 2, 4, 8, 13, 26, 52, 104, 251, 502, 1004, 2008, 3263, 6526, 13052, 26104.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 26104: a Harshad number: divisible by its digit sum 13.
- 2
26104 is composite. Its prime factorisation is
- 3
The divisors add up to 52920; without 26104 itself that is 26816, so 26104 is abundant (26816 is more than 26104). Euler's totient φ(26104) = 12000 numbers up to 26104 share no factor with it.
- 4
The digits of 26104 add up to 13, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 77 steps to reach 1.
LaTeX source of the formulas on this page
\[ 26104 = 2^{3} \times 13 \times 251 \]26104 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 16 |
| Sum of divisors | 52920 |
| Euler totient φ(n) | 12000 |
| Square | 681418816 |
| Cube | 17787756772864 |
| Square root | 161.567323 (= 2√6526) |
| Digit sum / digital root | 13 / 4 |
| Collatz steps to 1 | 77 |
| Scientific notation | 2.6104 × |
26104 in other forms
| Form | Value |
|---|---|
| In words | twenty-six thousand one hundred and four |
| Binary (base 2) | 110010111111000 |
| Octal (base 8) | 62770 |
| Hexadecimal (base 16) | 65F8 |
| Base 3 | 1022210211 |
| As time | 26104 seconds = 7 h 15 min 4 s |
Is 26104 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | Yes (26104 ÷ 2 = 13052) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | Yes (26104 ÷ 4 = 6526) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 4) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 4) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 1) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | Yes (26104 ÷ 8 = 3263) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 4) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 4) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 1) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 4) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 26104 a prime number?
No. 26104 = × 13 × 251, so it is divisible by 2.
What are the factors of 26104?
1, 2, 4, 8, 13, 26, 52, 104, 251, 502, 1004, 2008, 3263, 6526, 13052, 26104.
What is 26104 in binary?
110010111111000 (hexadecimal 65F8, octal 62770).
What is the square root of 26104?
About 161.5673, exactly 2√6526.
Is 26104 divisible by 3?
No. Its digits add up to 13, which is not a multiple of 3.
What is special about the number 26104?
26104 is a Harshad number: divisible by its digit sum 13.