The number 26027
26027 is a composite number with 4 divisors. Its prime factorisation is 17 × 1531. Divisors (4): 1, 17, 1531, 26027.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 26027: a Harshad number: divisible by its digit sum 17; a semiprime: 17 × 1531, the product of two primes.
- 2
26027 is composite. Its prime factorisation is
- 3
The divisors add up to 27576; without 26027 itself that is 1549, so 26027 is deficient (1549 is less than 26027). Euler's totient φ(26027) = 24480 numbers up to 26027 share no factor with it.
- 4
The digits of 26027 add up to 17, and repeating that until one digit is left gives the digital root 8. The Collatz sequence (halve if even, else 3n+1) takes 126 steps to reach 1.
LaTeX source of the formulas on this page
\[ 26027 = 17 \times 1531 \]
26027 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 27576 |
| Euler totient φ(n) | 24480 |
| Square | 677404729 |
| Cube | 17630812881683 |
| Square root | 161.328857 |
| Digit sum / digital root | 17 / 8 |
| Collatz steps to 1 | 126 |
| Scientific notation | 2.6027 × |
26027 in other forms
| Form | Value |
|---|---|
| In words | twenty-six thousand and twenty-seven |
| Binary (base 2) | 110010110101011 |
| Octal (base 8) | 62653 |
| Hexadecimal (base 16) | 65AB |
| Base 3 | 1022200222 |
| As time | 26027 seconds = 7 h 13 min 47 s |
Is 26027 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 2) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 1) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 3) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 8) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 7) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 1) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 11) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 26027 a prime number?
No. 26027 = 17 × 1531, so it is divisible by 17.
What are the factors of 26027?
1, 17, 1531, 26027.
What is 26027 in binary?
110010110101011 (hexadecimal 65AB, octal 62653).
What is the square root of 26027?
About 161.3289.
Is 26027 divisible by 3?
No. Its digits add up to 17, which is not a multiple of 3.
What is special about the number 26027?
26027 is a Harshad number: divisible by its digit sum 17; a semiprime: 17 × 1531, the product of two primes.