The number 26008
26008 is a composite number with 8 divisors. Its prime factorisation is × 3251. Divisors (8): 1, 2, 4, 8, 3251, 6502, 13004, 26008.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
26008 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
26008 is composite. Its prime factorisation is
- 3
The divisors add up to 48780; without 26008 itself that is 22772, so 26008 is deficient (22772 is less than 26008). Euler's totient φ(26008) = 13000 numbers up to 26008 share no factor with it.
- 4
The digits of 26008 add up to 16, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 139 steps to reach 1.
LaTeX source of the formulas on this page
\[ 26008 = 2^{3} \times 3251 \]26008 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 48780 |
| Euler totient φ(n) | 13000 |
| Square | 676416064 |
| Cube | 17592228992512 |
| Square root | 161.269960 (= 2√6502) |
| Digit sum / digital root | 16 / 7 |
| Collatz steps to 1 | 139 |
| Scientific notation | 2.6008 × |
26008 in other forms
| Form | Value |
|---|---|
| In words | twenty-six thousand and eight |
| Binary (base 2) | 110010110011000 |
| Octal (base 8) | 62630 |
| Hexadecimal (base 16) | 6598 |
| Base 3 | 1022200021 |
| As time | 26008 seconds = 7 h 13 min 28 s |
Is 26008 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | Yes (26008 ÷ 2 = 13004) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | Yes (26008 ÷ 4 = 6502) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 4) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 3) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | Yes (26008 ÷ 8 = 3251) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 7) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 8) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 4) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 4) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 26008 a prime number?
No. 26008 = × 3251, so it is divisible by 2.
What are the factors of 26008?
1, 2, 4, 8, 3251, 6502, 13004, 26008.
What is 26008 in binary?
110010110011000 (hexadecimal 6598, octal 62630).
What is the square root of 26008?
About 161.2700, exactly 2√6502.
Is 26008 divisible by 3?
No. Its digits add up to 16, which is not a multiple of 3.
What is special about the number 26008?
It is a composite number with 8 divisors.