The number 25993
25993 is a composite number with 8 divisors. Its prime factorisation is 11 × 17 × 139. Divisors (8): 1, 11, 17, 139, 187, 1529, 2363, 25993.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
25993 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
25993 is composite. Its prime factorisation is
- 3
The divisors add up to 30240; without 25993 itself that is 4247, so 25993 is deficient (4247 is less than 25993). Euler's totient φ(25993) = 22080 numbers up to 25993 share no factor with it.
- 4
The digits of 25993 add up to 28, and repeating that until one digit is left gives the digital root 1. The Collatz sequence (halve if even, else 3n+1) takes 126 steps to reach 1.
LaTeX source of the formulas on this page
\[ 25993 = 11 \times 17 \times 139 \]
25993 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 30240 |
| Euler totient φ(n) | 22080 |
| Square | 675636049 |
| Cube | 17561807821657 |
| Square root | 161.223447 |
| Digit sum / digital root | 28 / 1 |
| Collatz steps to 1 | 126 |
| Scientific notation | 2.5993 × |
25993 in other forms
| Form | Value |
|---|---|
| In words | twenty-five thousand nine hundred and ninety-three |
| Binary (base 2) | 110010110001001 |
| Octal (base 8) | 62611 |
| Hexadecimal (base 16) | 6589 |
| Base 3 | 1022122201 |
| As time | 25993 seconds = 7 h 13 min 13 s |
Is 25993 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 2) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 1) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | Yes (25993 ÷ 11 = 2363) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 1) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 25993 a prime number?
No. 25993 = 11 × 17 × 139, so it is divisible by 11.
What are the factors of 25993?
1, 11, 17, 139, 187, 1529, 2363, 25993.
What is 25993 in binary?
110010110001001 (hexadecimal 6589, octal 62611).
What is the square root of 25993?
About 161.2234.
Is 25993 divisible by 3?
No. Its digits add up to 28, which is not a multiple of 3.
What is special about the number 25993?
It is a composite number with 8 divisors.