The number 25823
25823 is a composite number with 12 divisors. Its prime factorisation is × 17 × 31. Divisors (12): 1, 7, 17, 31, 49, 119, 217, 527, 833, 1519, 3689, 25823.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
25823 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
25823 is composite. Its prime factorisation is
- 3
The divisors add up to 32832; without 25823 itself that is 7009, so 25823 is deficient (7009 is less than 25823). Euler's totient φ(25823) = 20160 numbers up to 25823 share no factor with it.
- 4
The digits of 25823 add up to 20, and repeating that until one digit is left gives the digital root 2. The Collatz sequence (halve if even, else 3n+1) takes 170 steps to reach 1.
LaTeX source of the formulas on this page
\[ 25823 = 7^{2} \times 17 \times 31 \]25823 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 12 |
| Sum of divisors | 32832 |
| Euler totient φ(n) | 20160 |
| Square | 666827329 |
| Cube | 17219482116767 |
| Square root | 160.695364 (= 7√527) |
| Digit sum / digital root | 20 / 2 |
| Collatz steps to 1 | 170 |
| Scientific notation | 2.5823 × |
25823 in other forms
| Form | Value |
|---|---|
| In words | twenty-five thousand eight hundred and twenty-three |
| Binary (base 2) | 110010011011111 |
| Octal (base 8) | 62337 |
| Hexadecimal (base 16) | 64DF |
| Base 3 | 1022102102 |
| As time | 25823 seconds = 7 h 10 min 23 s |
Is 25823 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | Yes (25823 ÷ 7 = 3689) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 2) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 6) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 11) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 25823 a prime number?
No. 25823 = × 17 × 31, so it is divisible by 7.
What are the factors of 25823?
1, 7, 17, 31, 49, 119, 217, 527, 833, 1519, 3689, 25823.
What is 25823 in binary?
110010011011111 (hexadecimal 64DF, octal 62337).
What is the square root of 25823?
About 160.6954, exactly 7√527.
Is 25823 divisible by 3?
No. Its digits add up to 20, which is not a multiple of 3.
What is special about the number 25823?
It is a composite number with 12 divisors.