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The number 25273

25273 is a composite number with 4 divisors. Its prime factorisation is 127 × 199. Divisors (4): 1, 127, 199, 25273.

Number

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How to work it out

  1. 1

    What is special about 25273: a happy number: repeatedly adding the squares of its digits reaches 1; a semiprime: 127 × 199, the product of two primes.

  2. 2

    25273 is composite. Its prime factorisation is

    25273=127×19925273 = 127 \times 199
  3. 3

    The divisors add up to 25600; without 25273 itself that is 327, so 25273 is deficient (327 is less than 25273). Euler's totient φ(25273) = 24948 numbers up to 25273 share no factor with it.

  4. 4

    The digits of 25273 add up to 19, and repeating that until one digit is left gives the digital root 1. The Collatz sequence (halve if even, else 3n+1) takes 64 steps to reach 1.

LaTeX source of the formulas on this page
\[ 25273 = 127 \times 199 \]

25273 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors25600
Euler totient φ(n)24948
Square638724529
Cube16142485021417
Square root158.974841
Digit sum / digital root19 / 1
Collatz steps to 164
Scientific notation2.5273 × 10410^{4}

25273 in other forms

FormValue
In wordstwenty-five thousand two hundred and seventy-three
Binary (base 2)110001010111001
Octal (base 8)61271
Hexadecimal (base 16)62B9
Base 31021200001
As time25273 seconds = 7 h 1 min 13 s

Is 25273 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 3)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 1)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 1)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 6)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 1)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 25273 a prime number?

No. 25273 = 127 × 199, so it is divisible by 127.

What are the factors of 25273?

1, 127, 199, 25273.

What is 25273 in binary?

110001010111001 (hexadecimal 62B9, octal 61271).

What is the square root of 25273?

About 158.9748.

Is 25273 divisible by 3?

No. Its digits add up to 19, which is not a multiple of 3.

What is special about the number 25273?

25273 is a happy number: repeatedly adding the squares of its digits reaches 1; a semiprime: 127 × 199, the product of two primes.

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    25273: is it prime? Factors, square root, binary, Roman numeral | WordGPT