The number 24993
24993 is a composite number with 6 divisors. Its prime factorisation is × 2777. Divisors (6): 1, 3, 9, 2777, 8331, 24993.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
24993 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
24993 is composite. Its prime factorisation is
- 3
The divisors add up to 36114; without 24993 itself that is 11121, so 24993 is deficient (11121 is less than 24993). Euler's totient φ(24993) = 16656 numbers up to 24993 share no factor with it.
- 4
The digits of 24993 add up to 27, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 51 steps to reach 1.
LaTeX source of the formulas on this page
\[ 24993 = 3^{2} \times 2777 \]24993 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 6 |
| Sum of divisors | 36114 |
| Euler totient φ(n) | 16656 |
| Square | 624650049 |
| Cube | 15611878674657 |
| Square root | 158.091746 (= 3√2777) |
| Digit sum / digital root | 27 / 9 |
| Collatz steps to 1 | 51 |
| Scientific notation | 2.4993 × |
24993 in other forms
| Form | Value |
|---|---|
| In words | twenty-four thousand nine hundred and ninety-three |
| Binary (base 2) | 110000110100001 |
| Octal (base 8) | 60641 |
| Hexadecimal (base 16) | 61A1 |
| Base 3 | 1021021200 |
| As time | 24993 seconds = 6 h 56 min 33 s |
Is 24993 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (24993 ÷ 3 = 8331) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 3) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (24993 ÷ 9 = 2777) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 1) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 9) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 24993 a prime number?
No. 24993 = × 2777, so it is divisible by 3.
What are the factors of 24993?
1, 3, 9, 2777, 8331, 24993.
What is 24993 in binary?
110000110100001 (hexadecimal 61A1, octal 60641).
What is the square root of 24993?
About 158.0917, exactly 3√2777.
Is 24993 divisible by 3?
Yes. Its digits add up to 27, a multiple of 3.
What is special about the number 24993?
It is a composite number with 6 divisors.