The number 24908
24908 is a composite number with 12 divisors. Its prime factorisation is × 13 × 479. Divisors (12): 1, 2, 4, 13, 26, 52, 479, 958, 1916, 6227, 12454, 24908.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
24908 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
24908 is composite. Its prime factorisation is
- 3
The divisors add up to 47040; without 24908 itself that is 22132, so 24908 is deficient (22132 is less than 24908). Euler's totient φ(24908) = 11472 numbers up to 24908 share no factor with it.
- 4
The digits of 24908 add up to 23, and repeating that until one digit is left gives the digital root 5. The Collatz sequence (halve if even, else 3n+1) takes 95 steps to reach 1.
LaTeX source of the formulas on this page
\[ 24908 = 2^{2} \times 13 \times 479 \]24908 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 12 |
| Sum of divisors | 47040 |
| Euler totient φ(n) | 11472 |
| Square | 620408464 |
| Cube | 15453134021312 |
| Square root | 157.822685 (= 2√6227) |
| Digit sum / digital root | 23 / 5 |
| Collatz steps to 1 | 95 |
| Scientific notation | 2.4908 × |
24908 in other forms
| Form | Value |
|---|---|
| In words | twenty-four thousand nine hundred and eight |
| Binary (base 2) | 110000101001100 |
| Octal (base 8) | 60514 |
| Hexadecimal (base 16) | 614C |
| Base 3 | 1021011112 |
| As time | 24908 seconds = 6 h 55 min 8 s |
Is 24908 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | Yes (24908 ÷ 2 = 12454) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | Yes (24908 ÷ 4 = 6227) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 2) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 2) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 4) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 5) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 8) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 4) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 8) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 24908 a prime number?
No. 24908 = × 13 × 479, so it is divisible by 2.
What are the factors of 24908?
1, 2, 4, 13, 26, 52, 479, 958, 1916, 6227, 12454, 24908.
What is 24908 in binary?
110000101001100 (hexadecimal 614C, octal 60514).
What is the square root of 24908?
About 157.8227, exactly 2√6227.
Is 24908 divisible by 3?
No. Its digits add up to 23, which is not a multiple of 3.
What is special about the number 24908?
It is a composite number with 12 divisors.