The number 23983
23983 is a composite number with 4 divisors. Its prime factorisation is 29 × 827. Divisors (4): 1, 29, 827, 23983.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 23983: a happy number: repeatedly adding the squares of its digits reaches 1; a semiprime: 29 × 827, the product of two primes.
- 2
23983 is composite. Its prime factorisation is
- 3
The divisors add up to 24840; without 23983 itself that is 857, so 23983 is deficient (857 is less than 23983). Euler's totient φ(23983) = 23128 numbers up to 23983 share no factor with it.
- 4
The digits of 23983 add up to 25, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 188 steps to reach 1.
LaTeX source of the formulas on this page
\[ 23983 = 29 \times 827 \]
23983 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 24840 |
| Euler totient φ(n) | 23128 |
| Square | 575184289 |
| Cube | 13794644803087 |
| Square root | 154.864457 |
| Digit sum / digital root | 25 / 7 |
| Collatz steps to 1 | 188 |
| Scientific notation | 2.3983 × |
23983 in other forms
| Form | Value |
|---|---|
| In words | twenty-three thousand nine hundred and eighty-three |
| Binary (base 2) | 101110110101111 |
| Octal (base 8) | 56657 |
| Hexadecimal (base 16) | 5DAF |
| Base 3 | 1012220021 |
| As time | 23983 seconds = 6 h 39 min 43 s |
Is 23983 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 1) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 7) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 3) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 7) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 23983 a prime number?
No. 23983 = 29 × 827, so it is divisible by 29.
What are the factors of 23983?
1, 29, 827, 23983.
What is 23983 in binary?
101110110101111 (hexadecimal 5DAF, octal 56657).
What is the square root of 23983?
About 154.8645.
Is 23983 divisible by 3?
No. Its digits add up to 25, which is not a multiple of 3.
What is special about the number 23983?
23983 is a happy number: repeatedly adding the squares of its digits reaches 1; a semiprime: 29 × 827, the product of two primes.