The number 23835
23835 is a composite number with 16 divisors. Its prime factorisation is 3 × 5 × 7 × 227. Divisors (16): 1, 3, 5, 7, 15, 21, 35, 105, 227, 681, 1135, 1589, 3405, 4767, 7945, 23835.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 23835: a Harshad number: divisible by its digit sum 21.
- 2
23835 is composite. Its prime factorisation is
- 3
The divisors add up to 43776; without 23835 itself that is 19941, so 23835 is deficient (19941 is less than 23835). Euler's totient φ(23835) = 10848 numbers up to 23835 share no factor with it.
- 4
The digits of 23835 add up to 21, and repeating that until one digit is left gives the digital root 3. The Collatz sequence (halve if even, else 3n+1) takes 100 steps to reach 1.
LaTeX source of the formulas on this page
\[ 23835 = 3 \times 5 \times 7 \times 227 \]
23835 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 16 |
| Sum of divisors | 43776 |
| Euler totient φ(n) | 10848 |
| Square | 568107225 |
| Cube | 13540835707875 |
| Square root | 154.385880 |
| Digit sum / digital root | 21 / 3 |
| Collatz steps to 1 | 100 |
| Scientific notation | 2.3835 × |
23835 in other forms
| Form | Value |
|---|---|
| In words | twenty-three thousand eight hundred and thirty-five |
| Binary (base 2) | 101110100011011 |
| Octal (base 8) | 56433 |
| Hexadecimal (base 16) | 5D1B |
| Base 3 | 1012200210 |
| As time | 23835 seconds = 6 h 37 min 15 s |
Is 23835 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (23835 ÷ 3 = 7945) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | Yes (23835 ÷ 5 = 4767) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | Yes (23835 ÷ 7 = 3405) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 3) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 3) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 5) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 9) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 3) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 23835 a prime number?
No. 23835 = 3 × 5 × 7 × 227, so it is divisible by 3.
What are the factors of 23835?
1, 3, 5, 7, 15, 21, 35, 105, 227, 681, 1135, 1589, 3405, 4767, 7945, 23835.
What is 23835 in binary?
101110100011011 (hexadecimal 5D1B, octal 56433).
What is the square root of 23835?
About 154.3859.
Is 23835 divisible by 3?
Yes. Its digits add up to 21, a multiple of 3.
What is special about the number 23835?
23835 is a Harshad number: divisible by its digit sum 21.