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The number 23483

23483 is a composite number with 4 divisors. Its prime factorisation is 23 × 1021. Divisors (4): 1, 23, 1021, 23483.

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How to work it out

  1. 1

    What is special about 23483: a semiprime: 23 × 1021, the product of two primes.

  2. 2

    23483 is composite. Its prime factorisation is

    23483=23×102123483 = 23 \times 1021
  3. 3

    The divisors add up to 24528; without 23483 itself that is 1045, so 23483 is deficient (1045 is less than 23483). Euler's totient φ(23483) = 22440 numbers up to 23483 share no factor with it.

  4. 4

    The digits of 23483 add up to 20, and repeating that until one digit is left gives the digital root 2. The Collatz sequence (halve if even, else 3n+1) takes 51 steps to reach 1.

LaTeX source of the formulas on this page
\[ 23483 = 23 \times 1021 \]

23483 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors24528
Euler totient φ(n)22440
Square551451289
Cube12949730619587
Square root153.241639
Digit sum / digital root20 / 2
Collatz steps to 151
Scientific notation2.3483 × 10410^{4}

23483 in other forms

FormValue
In wordstwenty-three thousand four hundred and eighty-three
Binary (base 2)101101110111011
Octal (base 8)55673
Hexadecimal (base 16)5BBB
Base 31012012202
As time23483 seconds = 6 h 31 min 23 s

Is 23483 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 2)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 5)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 5)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 3)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 2)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 9)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 11)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 23483 a prime number?

No. 23483 = 23 × 1021, so it is divisible by 23.

What are the factors of 23483?

1, 23, 1021, 23483.

What is 23483 in binary?

101101110111011 (hexadecimal 5BBB, octal 55673).

What is the square root of 23483?

About 153.2416.

Is 23483 divisible by 3?

No. Its digits add up to 20, which is not a multiple of 3.

What is special about the number 23483?

23483 is a semiprime: 23 × 1021, the product of two primes.

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