The number 23439
23439 is a composite number with 8 divisors. Its prime factorisation is 3 × 13 × 601. Divisors (8): 1, 3, 13, 39, 601, 1803, 7813, 23439.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
23439 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
23439 is composite. Its prime factorisation is
- 3
The divisors add up to 33712; without 23439 itself that is 10273, so 23439 is deficient (10273 is less than 23439). Euler's totient φ(23439) = 14400 numbers up to 23439 share no factor with it.
- 4
The digits of 23439 add up to 21, and repeating that until one digit is left gives the digital root 3. The Collatz sequence (halve if even, else 3n+1) takes 144 steps to reach 1.
LaTeX source of the formulas on this page
\[ 23439 = 3 \times 13 \times 601 \]
23439 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 33712 |
| Euler totient φ(n) | 14400 |
| Square | 549386721 |
| Cube | 12877075353519 |
| Square root | 153.098008 |
| Digit sum / digital root | 21 / 3 |
| Collatz steps to 1 | 144 |
| Scientific notation | 2.3439 × |
23439 in other forms
| Form | Value |
|---|---|
| In words | twenty-three thousand four hundred and thirty-nine |
| Binary (base 2) | 101101110001111 |
| Octal (base 8) | 55617 |
| Hexadecimal (base 16) | 5B8F |
| Base 3 | 1012011010 |
| As time | 23439 seconds = 6 h 30 min 39 s |
Is 23439 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (23439 ÷ 3 = 7813) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 4) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 3) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 3) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 9) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 9) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 3) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 23439 a prime number?
No. 23439 = 3 × 13 × 601, so it is divisible by 3.
What are the factors of 23439?
1, 3, 13, 39, 601, 1803, 7813, 23439.
What is 23439 in binary?
101101110001111 (hexadecimal 5B8F, octal 55617).
What is the square root of 23439?
About 153.0980.
Is 23439 divisible by 3?
Yes. Its digits add up to 21, a multiple of 3.
What is special about the number 23439?
It is a composite number with 8 divisors.