The number 23428
23428 is a composite number with 6 divisors. Its prime factorisation is × 5857. Divisors (6): 1, 2, 4, 5857, 11714, 23428.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 23428: a happy number: repeatedly adding the squares of its digits reaches 1.
- 2
23428 is composite. Its prime factorisation is
- 3
The divisors add up to 41006; without 23428 itself that is 17578, so 23428 is deficient (17578 is less than 23428). Euler's totient φ(23428) = 11712 numbers up to 23428 share no factor with it.
- 4
The digits of 23428 add up to 19, and repeating that until one digit is left gives the digital root 1. The Collatz sequence (halve if even, else 3n+1) takes 144 steps to reach 1.
LaTeX source of the formulas on this page
\[ 23428 = 2^{2} \times 5857 \]23428 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 6 |
| Sum of divisors | 41006 |
| Euler totient φ(n) | 11712 |
| Square | 548871184 |
| Cube | 12858954098752 |
| Square root | 153.062079 (= 2√5857) |
| Digit sum / digital root | 19 / 1 |
| Collatz steps to 1 | 144 |
| Scientific notation | 2.3428 × |
23428 in other forms
| Form | Value |
|---|---|
| In words | twenty-three thousand four hundred and twenty-eight |
| Binary (base 2) | 101101110000100 |
| Octal (base 8) | 55604 |
| Hexadecimal (base 16) | 5B84 |
| Base 3 | 1012010201 |
| As time | 23428 seconds = 6 h 30 min 28 s |
Is 23428 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | Yes (23428 ÷ 2 = 11714) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | Yes (23428 ÷ 4 = 5857) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 4) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 6) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 4) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 1) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 8) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 9) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 4) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 23428 a prime number?
No. 23428 = × 5857, so it is divisible by 2.
What are the factors of 23428?
1, 2, 4, 5857, 11714, 23428.
What is 23428 in binary?
101101110000100 (hexadecimal 5B84, octal 55604).
What is the square root of 23428?
About 153.0621, exactly 2√5857.
Is 23428 divisible by 3?
No. Its digits add up to 19, which is not a multiple of 3.
What is special about the number 23428?
23428 is a happy number: repeatedly adding the squares of its digits reaches 1.