The number 23391
23391 is a composite number with 12 divisors. Its prime factorisation is × 23 × 113. Divisors (12): 1, 3, 9, 23, 69, 113, 207, 339, 1017, 2599, 7797, 23391.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
23391 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
23391 is composite. Its prime factorisation is
- 3
The divisors add up to 35568; without 23391 itself that is 12177, so 23391 is deficient (12177 is less than 23391). Euler's totient φ(23391) = 14784 numbers up to 23391 share no factor with it.
- 4
The digits of 23391 add up to 18, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 82 steps to reach 1.
LaTeX source of the formulas on this page
\[ 23391 = 3^{2} \times 23 \times 113 \]23391 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 12 |
| Sum of divisors | 35568 |
| Euler totient φ(n) | 14784 |
| Square | 547138881 |
| Cube | 12798125565471 |
| Square root | 152.941165 (= 3√2599) |
| Digit sum / digital root | 18 / 9 |
| Collatz steps to 1 | 82 |
| Scientific notation | 2.3391 × |
23391 in other forms
| Form | Value |
|---|---|
| In words | twenty-three thousand three hundred and ninety-one |
| Binary (base 2) | 101101101011111 |
| Octal (base 8) | 55537 |
| Hexadecimal (base 16) | 5B5F |
| Base 3 | 1012002100 |
| As time | 23391 seconds = 6 h 29 min 51 s |
Is 23391 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (23391 ÷ 3 = 7797) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 1) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 4) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (23391 ÷ 9 = 2599) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 1) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 5) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 3) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 23391 a prime number?
No. 23391 = × 23 × 113, so it is divisible by 3.
What are the factors of 23391?
1, 3, 9, 23, 69, 113, 207, 339, 1017, 2599, 7797, 23391.
What is 23391 in binary?
101101101011111 (hexadecimal 5B5F, octal 55537).
What is the square root of 23391?
About 152.9412, exactly 3√2599.
Is 23391 divisible by 3?
Yes. Its digits add up to 18, a multiple of 3.
What is special about the number 23391?
It is a composite number with 12 divisors.