The number 23301
23301 is a composite number with 8 divisors. Its prime factorisation is × 863. Divisors (8): 1, 3, 9, 27, 863, 2589, 7767, 23301.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 23301: a happy number: repeatedly adding the squares of its digits reaches 1; a Harshad number: divisible by its digit sum 9.
- 2
23301 is composite. Its prime factorisation is
- 3
The divisors add up to 34560; without 23301 itself that is 11259, so 23301 is deficient (11259 is less than 23301). Euler's totient φ(23301) = 15516 numbers up to 23301 share no factor with it.
- 4
The digits of 23301 add up to 9, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 51 steps to reach 1.
LaTeX source of the formulas on this page
\[ 23301 = 3^{3} \times 863 \]23301 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 34560 |
| Euler totient φ(n) | 15516 |
| Square | 542936601 |
| Cube | 12650965739901 |
| Square root | 152.646651 (= 3√2589) |
| Digit sum / digital root | 9 / 9 |
| Collatz steps to 1 | 51 |
| Scientific notation | 2.3301 × |
23301 in other forms
| Form | Value |
|---|---|
| In words | twenty-three thousand three hundred and one |
| Binary (base 2) | 101101100000101 |
| Octal (base 8) | 55405 |
| Hexadecimal (base 16) | 5B05 |
| Base 3 | 1011222000 |
| As time | 23301 seconds = 6 h 28 min 21 s |
Is 23301 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (23301 ÷ 3 = 7767) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 1) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 5) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 5) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (23301 ÷ 9 = 2589) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 1) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 3) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 9) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 23301 a prime number?
No. 23301 = × 863, so it is divisible by 3.
What are the factors of 23301?
1, 3, 9, 27, 863, 2589, 7767, 23301.
What is 23301 in binary?
101101100000101 (hexadecimal 5B05, octal 55405).
What is the square root of 23301?
About 152.6467, exactly 3√2589.
Is 23301 divisible by 3?
Yes. Its digits add up to 9, a multiple of 3.
What is special about the number 23301?
23301 is a happy number: repeatedly adding the squares of its digits reaches 1; a Harshad number: divisible by its digit sum 9.