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The number 23273

23273 is a composite number with 6 divisors. Its prime factorisation is 17 Ɨ 37237^{2}. Divisors (6): 1, 17, 37, 629, 1369, 23273.

Number

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How to work it out

  1. 1

    What is special about 23273: a Harshad number: divisible by its digit sum 17.

  2. 2

    23273 is composite. Its prime factorisation is

    23273=17Ɨ37223273 = 17 \times 37^{2}
  3. 3

    The divisors add up to 25326; without 23273 itself that is 2053, so 23273 is deficient (2053 is less than 23273). Euler's totient φ(23273) = 21312 numbers up to 23273 share no factor with it.

  4. 4

    The digits of 23273 add up to 17, and repeating that until one digit is left gives the digital root 8. The Collatz sequence (halve if even, else 3n+1) takes 82 steps to reach 1.

LaTeX source of the formulas on this page
\[ 23273 = 17 \times 37^{2} \]

23273 at a glance

PropertyValue
Typecomposite
Number of divisors6
Sum of divisors25326
Euler totient φ(n)21312
Square541632529
Cube12605413847417
Square root152.554908 (= 37√17)
Digit sum / digital root17 / 8
Collatz steps to 182
Scientific notation2.3273 Ɨ 10410^{4}

23273 in other forms

FormValue
In wordstwenty-three thousand two hundred and seventy-three
Binary (base 2)101101011101001
Octal (base 8)55351
Hexadecimal (base 16)5AE9
Base 31011220222
As time23273 seconds = 6 h 27 min 53 s

Is 23273 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 2)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 5)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 5)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 1)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 8)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 8)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 5)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 23273 a prime number?

No. 23273 = 17 Ɨ 37237^{2}, so it is divisible by 17.

What are the factors of 23273?

1, 17, 37, 629, 1369, 23273.

What is 23273 in binary?

101101011101001 (hexadecimal 5AE9, octal 55351).

What is the square root of 23273?

About 152.5549, exactly 37√17.

Is 23273 divisible by 3?

No. Its digits add up to 17, which is not a multiple of 3.

What is special about the number 23273?

23273 is a Harshad number: divisible by its digit sum 17.

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    23273: is it prime? Factors, square root, binary, Roman numeral | WordGPT