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The number 22007

22007 is a composite number with 4 divisors. Its prime factorisation is 59 × 373. Divisors (4): 1, 59, 373, 22007.

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How to work it out

  1. 1

    What is special about 22007: a semiprime: 59 × 373, the product of two primes.

  2. 2

    22007 is composite. Its prime factorisation is

    22007=59×37322007 = 59 \times 373
  3. 3

    The divisors add up to 22440; without 22007 itself that is 433, so 22007 is deficient (433 is less than 22007). Euler's totient φ(22007) = 21576 numbers up to 22007 share no factor with it.

  4. 4

    The digits of 22007 add up to 11, and repeating that until one digit is left gives the digital root 2. The Collatz sequence (halve if even, else 3n+1) takes 74 steps to reach 1.

LaTeX source of the formulas on this page
\[ 22007 = 59 \times 373 \]

22007 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors22440
Euler totient φ(n)21576
Square484308049
Cube10658167234343
Square root148.347565
Digit sum / digital root11 / 2
Collatz steps to 174
Scientific notation2.2007 × 10410^{4}

22007 in other forms

FormValue
In wordstwenty-two thousand and seven
Binary (base 2)101010111110111
Octal (base 8)52767
Hexadecimal (base 16)55F7
Base 31010012002
As time22007 seconds = 6 h 6 min 47 s

Is 22007 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 2)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 2)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 5)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 6)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 7)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 2)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 7)A number is divisible by 10 if the last digit is 0.
11No (remainder 7)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 11)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 22007 a prime number?

No. 22007 = 59 × 373, so it is divisible by 59.

What are the factors of 22007?

1, 59, 373, 22007.

What is 22007 in binary?

101010111110111 (hexadecimal 55F7, octal 52767).

What is the square root of 22007?

About 148.3476.

Is 22007 divisible by 3?

No. Its digits add up to 11, which is not a multiple of 3.

What is special about the number 22007?

22007 is a semiprime: 59 × 373, the product of two primes.

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