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The number 21955

21955 is a composite number with 4 divisors. Its prime factorisation is 5 × 4391. Divisors (4): 1, 5, 4391, 21955.

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How to work it out

  1. 1

    What is special about 21955: a semiprime: 5 × 4391, the product of two primes.

  2. 2

    21955 is composite. Its prime factorisation is

    21955=5×439121955 = 5 \times 4391
  3. 3

    The divisors add up to 26352; without 21955 itself that is 4397, so 21955 is deficient (4397 is less than 21955). Euler's totient φ(21955) = 17560 numbers up to 21955 share no factor with it.

  4. 4

    The digits of 21955 add up to 22, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 149 steps to reach 1.

LaTeX source of the formulas on this page
\[ 21955 = 5 \times 4391 \]

21955 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors26352
Euler totient φ(n)17560
Square482022025
Cube10582793558875
Square root148.172197
Digit sum / digital root22 / 4
Collatz steps to 1149
Scientific notation2.1955 × 10410^{4}

21955 in other forms

FormValue
In wordstwenty-one thousand nine hundred and fifty-five
Binary (base 2)101010111000011
Octal (base 8)52703
Hexadecimal (base 16)55C3
Base 31010010011
As time21955 seconds = 6 h 5 min 55 s

Is 21955 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5Yes (21955 ÷ 5 = 4391)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 3)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 3)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 4)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 5)A number is divisible by 10 if the last digit is 0.
11No (remainder 10)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 7)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 21955 a prime number?

No. 21955 = 5 × 4391, so it is divisible by 5.

What are the factors of 21955?

1, 5, 4391, 21955.

What is 21955 in binary?

101010111000011 (hexadecimal 55C3, octal 52703).

What is the square root of 21955?

About 148.1722.

Is 21955 divisible by 3?

No. Its digits add up to 22, which is not a multiple of 3.

What is special about the number 21955?

21955 is a semiprime: 5 × 4391, the product of two primes.

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